如何将列表作为参数传递给 Scala 中的对象

Question

I have created object which takes list as argument but when I passed list to execute object,I get error.Please guide,code is as follows

object myobj {
    private var dateList  = List[String]()
    private val NPARAMS = 1

    private def parseArgs(args:Array[String]):Unit ={
        if(args.length < NPARAMS){
            println("Insufficient No of Parameters")
            System.exit(1)
        }
        var i = 0
        dateList = List(args(i))
    }
    // Some code...
}

Now executing object

val dateList =  ("2019-01-01","2019-01-02")

myobj.main(Array(dateList))

Error

dateList: (String, String) = (2019-01-01,2019-01-02)

<console>:37: error: type mismatch;
 found   : (String, String)
 required: String
       myobj.main(Array(dateList))
                        ^

Answer 1

Your variable dateList is a tuple. In scala the notation (TypeA, TypeB) as in your error message is a shorthand for scala.Tuple2[TypeA, TypeB].

What you want is an Array Array("arg1", "arg2") .

Answer 2

Did you mean

val dateList =  Array("2019-01-01","2019-01-02")
myobj.main(dateList)

?