[英]How to query database items from models.py in Django?
I have different model. 我有不同的型号。 Choices of Multiselctfield of one model is dependent on another model.So , database has to be queried inside model.py While doing so, this causes problem in migration.
一个模型的Multiselctfield的选择取决于另一个模型。因此,必须在model.py中查询数据库,这会导致迁移问题。 (Table doesn't exist error)
(表不存在错误)
class Invigilator(models.Model):
---
# this method queries Shift objects and Examroom
def get_invigilator_assignment_list ():
assignment = []
shifts = Shift.objects.all()
for shift in shifts:
rooms= ExamRoom.objects.all()
for room in rooms:
assign = str (shift.shiftName)+ " " +str (room.name)
assignment.append (assign)
return assignment
assignment_choice = []
assign = get_invigilator_assignment_list()
i = 0
for assignm in assign:
datatuple = (i,assignm)
assignment_choice.append(datatuple)
i= i+1
ASSIGNMENT_CHOICE = tuple(assignment_choice)
assignment =MultiSelectField (choices = ASSIGNMENT_CHOICE, blank = True, verbose_name="Assignments")
You cannot add dynamic choices because they are all stored in the migration files and table info. 您无法添加动态选择,因为它们都存储在迁移文件和表信息中。 If Django lets you do that, this means that everytime someone adds a record to those 2 models, a new migration should be created and the db should be changed.
如果Django允许您这样做,则意味着每次有人向这2个模型添加一条记录时,都应创建一个新的迁移并更改数据库。 You must approach this problem differently.
您必须以不同的方式处理此问题。
As far as I know django-smart-selects has a ChainedManyToMany
field which can do the trick. 据我所知, django-smart-
ChainedManyToMany
有一个ChainedManyToMany
字段可以解决问题。
Here is an example from the repo. 这是仓库中的一个例子。
from smart_selects.db_fields import ChainedManyToManyField
class Publication(models.Model):
name = models.CharField(max_length=255)
class Writer(models.Model):
name = models.CharField(max_length=255)
publications = models.ManyToManyField('Publication', blank=True, null=True)
class Book(models.Model):
publication = models.ForeignKey(Publication)
writer = ChainedManyToManyField(
Writer,
chained_field="publication",
chained_model_field="publications")
name = models.CharField(max_length=255)
This cannot be done in the model and doesn't make sense. 这无法在模型中完成,也没有意义。 It's like you're trying to create a column in a table with a certain fixed set of choices (what is
MultiSelecField
anyway?), but when someone later adds a new row in the Shift
or ExamRoom
table, the initial column choices have to change again. 就像您要在具有某些固定选择集的表中创建一列(无论如何是
MultiSelecField
?),但是当有人稍后在Shift
或ExamRoom
表中添加新行时,必须更改初始列选择再次。
You can 您可以
assignment
column a simple CharField
and create the choices dynamically when creating the form assignment
列CharField
简单的CharField
并在创建表单时动态创建选择 assignment
is a combination of Shift
and ExamRoom
, I would create a through relationship: assignment
是Shift
和ExamRoom
的组合,因此我将创建一个直通关系: shifts = models.ManyToManyField(Shift, through=Assignment)
class Assignment(Model):
room = ForeignKey(ExamRoom)
shift = ForeignKey(Shift)
invigilator = ForeignKey(Invigilator)
When creating the relationship, you'd have to pick a Shift and a Room which would create the Assignment
object. 创建关系时,必须选择一个Shift和一个Room,以创建
Assignment
对象。 Then you can query things like invigilator.shifts.all()
or invigilator.assignment_set.first().room
. 然后,您可以查询诸如
invigilator.shifts.all()
或invigilator.assignment_set.first().room
。
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