如何为在XPath中传递的char A到Z提供循环，这可能是我们不需要多次编写XPath

Question

Are there any solutions for XPath?
I want to traverse from char ' A ' to ' Z ', but the problem is which is indide the XPath...

So I think we solve this by loop, but I do not know how to provide s loop for that... For code optimization we do not need to write XPath for multiple times..

I have tried it by loop, but it doesn't work.

WebElement A = driver.findElement(By.xpath("//a[text()='**A**']"));
act.click(A).perform();
char c = 'A';
for (c='A';c<='Z';c++)
{
     String s = Character.toString(c);          
}

Answer 1

Use String formatter - define a "template" with the fixed structure of the string, and the format specifier.
Presuming you want to replace the "A" in the "**A**" text:

String templ = "//a[text()='**%s**']";
for (char c='A'; c<='Z'; c++){
     WebElement A = driver.findElement(By.xpath(String.format(templ, c)));
     /* if you want to see the constructed string/locator:
     System.out.println(String.format(templ, c)); */
     act.click(A).perform();
}

Answer 2

Make the xpath selector dynamic, this is sample logic, you can improve later, try this:

String[] letters = {"A","B","C"....};
Actions action = new Actions(driver);

for (int i=0; i<letters.length(); i++)
{
    WebElement element = driver.findElement(By.xpath("//a[text()=\"**" + letters[i] + "**\"]"));
    action.moveToElement(element).click().perform();
}