在Python中一定数量的字符出现多于一次之后，如何修剪字符串？

Question

I am trying to scan a string and every time it reads a certain character 3 times, I would like to cut the remaining string

for example: The string "C:\\Temp\\Test\\Documents\\Test.doc" would turn into "C:\\Temp\\Test\\"

Every time the string hits "\\" 3 times it should trim the string

here is my code that I am working on

prefix = ["" for x in range(size)]
num = 0
...            
...            
            for char in os.path.realpath(src):
                for x in prefix:
                    x = char
                    if x =='\': # I get an error here
                        num = num + 1
                    if num == 3:
                        break
                    print (num)

            print(prefix)
...
...

the os.path.realpath(src) is the string with with the filepath. The "prefix" variable is the string array that I want to store the trimmed string.

Please let me know what I need to fix or if there is a simpler way to perform this.

Answer 1

Do split and then slice list to grab required and join :

s = 'C:\Temp\Test\Documents\Test.doc'

print('\\'.join(s.split('\\')[:3]) + '\\')
# C:\Temp\Test\

Note that \\ (backslash) is an escaping character. To specifically mean a backslash, force it to be a backslash by adding a backslash before backslash \\\\ , thereby removing the special meaning of backslash.

Answer 2

In python the backslash character is used as an escape character. If you do \\n it does a newline, \\t does a tab. There are many other things such as \\" lets you do a quote in a string. If you want a regular backslash you should do "\\\\"

Answer 3

try

s = "C:\\Temp\\Test\\Documents\\Test.doc"
answer = '\\'.join(s.split('\\', 3)[:3])

Answer 4

Something like this would do..

x = "C:\Temp\Test\Documents\Test.doc"
print('\\'.join(x.split("\\")[:3])+"\\")