[英]Search in files line by line python 2.7 in an array
I have a file looks like this: 我有一个文件看起来像这样:
(...)
- src: git+[server]
name: main
version: master
- src: git+[server]
name: sec
version: master
- src: git+[server]
name: compiler
version: master
- src: git[server]
name: libs
version: master
- src: git[server]
name: crosscomp
version: master
(...)
and I only want to change the version after 我只想在之后更改版本
name: main
名称:主要
and 和
name: sec
名称:秒
So my idea was to read the whole file line by line into an array and check if the line begins with the name: master or name: sec. 因此,我的想法是将整个文件逐行读取到数组中,并检查该行是否以名称:master或name:sec开头。 (with
startswith()
) (带有
startswith()
)
But how can I access the line after the finding? 但是,发现后如何进入生产线?
You can process the lines in pairs and update the next line whenever the you find a matching line. 您可以成对处理这些行,并在找到匹配的行时更新下一行。 You'll need to overwrite the contents of the file with new lines at the end.
您需要在末尾用新行覆盖文件的内容。
with open(filename, 'r+') as f:
lines = f.readlines()
for i in range(len(lines)-1):
if 'name: main' in lines[i] or 'name: sec' in lines[i]:
lines[i+1] = lines[i+1].replace('master', 'newversion')
f.seek(0)
f.truncate()
f.writelines(lines)
maseterIndex = [i for i, x in enumerate(array) if x == "name: master"]
secIndex = [i for i, x in enumerate(array) if x == "name: sec"]
mergedlist = maseterIndex + secIndex
for index in mergedlist:
#do something with next line
print array[index+1]
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