[英]How to use go tool compile?
Simple code recursion and tails 简单的代码递归和尾部
package main
import "fmt"
func TailRecursive(number int, product int) int {
product = product + number
if number == 1 {
return product
}
return TailRecursive(number-1, product)
}
func main() {
answer := TailRecursive(5, 0)
fmt.Printf("Recursive: %d\n", answer)
}
When I try tool compile 当我尝试工具编译时
go tool compile 6g -S ./g9.go > assembly.asm
I got this 我懂了
cat assembly.asm
6g:0:0: open 6g: no such file or directory
My kernel architecture 我的内核架构
x86_64 x86_64 x86_64 GNU/Linux
How to use go tool compile to get the proper assembly output? 如何使用go工具编译以获得正确的程序集输出?
Drop the 6g (it's now known as compile
) 删除6g(现在称为compile
)
go tool compile -S ./g9.go > assembly.asm
Output 输出量
"".TailRecursive STEXT size=107 args=0x18 locals=0x20
0x0000 00000 (g9.go:5) TEXT "".TailRecursive(SB), $32-24
0x0000 00000 (g9.go:5) MOVQ (TLS), CX
0x0009 00009 (g9.go:5) CMPQ SP, 16(CX)
0x000d 00013 (g9.go:5) JLS 100
0x000f 00015 (g9.go:5) SUBQ $32, SP
0x0013 00019 (g9.go:5) MOVQ BP, 24(SP)
0x0018 00024 (g9.go:5) LEAQ 24(SP), BP
0x001d 00029 (g9.go:5) FUNCDATA $0, gclocals·33cdeccccebe80329f1fdbee7f5874cb(SB)
0x001d 00029 (g9.go:5) FUNCDATA $1, gclocals·33cdeccccebe80329f1fdbee7f5874cb(SB)
0x001d 00029 (g9.go:5) FUNCDATA $3, gclocals·33cdeccccebe80329f1fdbee7f5874cb(SB)
0x001d 00029 (g9.go:7) PCDATA $2, $0
0x001d 00029 (g9.go:7) PCDATA $0, $0
0x001d 00029 (g9.go:7) MOVQ "".number+40(SP), AX
0x0022 00034 (g9.go:7) MOVQ "".product+48(SP), CX
0x0027 00039 (g9.go:7) ADDQ AX, CX
0x002a 00042 (g9.go:9) CMPQ AX, $1
0x002e 00046 (g9.go:9) JNE 63
0x0030 00048 (g9.go:11) MOVQ CX, "".~r2+56(SP)
0x0035 00053 (g9.go:11) MOVQ 24(SP), BP
0x003a 00058 (g9.go:11) ADDQ $32, SP
0x003e 00062 (g9.go:11) RET
...
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