[英]Regex for comma separated 3 letter words
I want to create a regex for exactly 3 letter words only, separated by commas. 我只想为正好3个字母的单词创建一个正则表达式,并用逗号分隔。 3 letter words can be padded with space(at most 1 on each side)
3个字母词可以用空格填充(每边最多1个)
Valid Examples: 有效示例:
ORD
JFK, LAX
ABC,DEF, GHK,REW, ASD
Invalid Examples: 无效的示例:
ORDA
OR
ORD,
JFK, LA
I tried the following but couldn't get it to work. 我尝试了以下操作,但无法正常工作。
^(?:[A-Z ]+,)*[A-Z ]{3} +$
Try this pattern: 试试这个模式:
^[A-Z]{3}(?:[ ]?,[ ]?[A-Z]{3})*$
This pattern matches an initial three letter word, followed by two more terms separated by a comma with optional spaces. 此模式与第一个三个字母的单词匹配,后跟两个以上的单词,并用逗号分隔,并带有可选的空格。
Try this: ^([ ]?[AZ]{3}[ ]?,)*([ ]?[AZ]{3}[ ]?)+$
试试这个:
^([ ]?[AZ]{3}[ ]?,)*([ ]?[AZ]{3}[ ]?)+$
https://regex101.com/r/HFeN0D/2/ https://regex101.com/r/HFeN0D/2/
It matches at least one three letter word (with spaces), preceded by any number of words three letter words with commas after them. 它匹配至少一个三个字母的单词(带空格),后跟任意数量的单词,三个字母后面带有逗号。
You can do this with the pattern: ^((:? ?[AZ]{3} ?,)*(?: ?[AZ]{3} ?))+$
您可以使用以下模式执行此操作:
^((:? ?[AZ]{3} ?,)*(?: ?[AZ]{3} ?))+$
var str = `ORD JFK, LAX ABC,DEF, GHK,REW, ASD ORDA OR ORD, JFK, LA`; let result = str.match(/^((:? ?[AZ]{3} ?,)*(?: ?[AZ]{3} ?))+$/gm); document.getElementById('match').innerHTML = result.join('<br>');
<p id="match"></p>
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