雪花中的 generate_series() 等效项

Question

我正在尝试找到与 generate_series() （PostgreSQL 语法）等效的雪花。

SELECT generate_series(timestamp '2017-11-01', CURRENT_DATE, '1 day')

Answer 1

Just wanted to expand on Marcin Zukowski 's comment to say that these gaps started to show up almost immediately after using a date range generated this way in a JOIN .

We ultimately ended up doing this instead!

select
  dateadd(
    day,
    '-' || row_number() over (order by null),
    dateadd(day, '+1', current_date())
  ) as date
from table (generator(rowcount => 90))

Answer 2

I had a similar problem and found an approach, which avoids the issue of a generator requiring a constant value by using a session variable in addition to the already great answers here. This is closest to the requirement of the OP to my mind.

-- set parameter to be used as generator "constant" including the start day
set num_days =  (Select datediff(day, TO_DATE('2017-11-01','YYYY-MM-DD'), current_date()+1));
-- use parameter in bcrowell's answer now
select
  dateadd(
    day,
    '-' || row_number() over (order by null),
    dateadd(day, '+1', current_date())
  ) as date
from table (generator(rowcount => ($num_days)));
-- clean up previously set variable
unset num_days;

Answer 3

Adding this answer for completitude, in case you have an initial and last date:

select -1 + row_number() over(order by 0) i, start_date + i generated_date 
from (select '2020-01-01'::date start_date, '2020-01-15'::date end_date)
join table(generator(rowcount => 10000 )) x
qualify i < 1 + end_date - start_date

Answer 4

I found the generator function in Snowflake quite limiting for all but the simplest use cases. For example, it was not clear how to take a single row specification, explode it into a table of dates and join it back to the original spec table.

Here is an alternative that uses recursive CTEs.

-- A 2 row table that contains "specs" for a date range
create local temp table date_spec as
    select 1 as id, '2022-04-01'::date as start_date, current_date() as end_date
    union all
    select 2, '2022-03-01', '2032-03-30'
;

with explode_date(id, date, next_date, end_date) as (
    select
        id
      , start_date as date          -- start_date is the first date
      , date + 1 as next_date       -- next_date is the date of for the subsequent row in the recursive cte
      , end_date
    from date_spec

    union all

    select
        ds.id
      , ed.next_date                -- the current_date is the value of next_date from above
      , ed.next_date + 1
      , ds.end_date
    from date_spec ds
    join explode_date ed
      on ed.id = ds.id
    where ed.date <= ed.end_date    -- keep running until you hit the end_date
)

select * from explode_date
order by id, date desc
;

Answer 5

WITH RECURSIVE rec_cte AS (
    -- start date
    SELECT '2017-11-01'::DATE as dt
    UNION ALL
    SELECT DATEADD('day',1,dt) as dt
    FROM rec_cte
    -- end date (inclusive)
    WHERE dt < current_date()
)
SELECT * FROM rec_cte

Answer 6

This is how I was able to generate a series of dates in Snowflake. I set row count to 1095 to get 3 years worth of dates, you can of course change that to whatever suits your use case

select 
    dateadd(day, '-' || seq4(), current_date()) as dte 
from 
    table 
       (generator(rowcount => 1095))

Originally found here

EDIT: This solution is not correct. seq4 does not guarantee a sequence without gaps. Please follow other answers, not this one. Thanks @Marcin Zukowski for pointing that out.