[英]Transform XML using XSLT in JAVA
I have an example in Java using XSLT 3.0 to merge 2 xml files (personne1 , personne2) using XSLT 3.0 (xsltfilePersonnes.xsl).我在 Java 中有一个示例,使用 XSLT 3.0 合并使用 XSLT 3.0 (xsltfilePersonnes.xsl) 的 2 个 xml 文件(personne1、personne2)。
I m using Saxon 9.8 (version for XSLT 3.0).我正在使用 Saxon 9.8(XSLT 3.0 版本)。 Tried so far :
到目前为止尝试过:
in command line I run this command line :在命令行中,我运行此命令行:
C:\test2>java -jar saxon-he-9.8.0-1.jar personne1.xml xsltFilePersonnes.xsl -o:resultFile.xml
it run without error and the fileResult was as expected it merge the two files(personne1 and personne2) in the resultfile.xml, but when I run java main class I got this error :它运行没有错误,fileResult 符合预期,它合并了 resultfile.xml 中的两个文件(personne1 和 personne2),但是当我运行 java 主类时,我收到了这个错误:
Recoverable error on line 1 column 39 of file:C:\test2\xsltFilePersonnes.xsl:
SXXP0003: Error reported by XML parser:
file:C:\test2\xsltFilePersonnes.xsl<Line 1, Column 39>
: XML-20180: (Error) User Supplied NodeFactory returned a Null Pointer.: Invalid URI for stylesheet: file:C:test2\xsltFilePersonnes.xsl
any help is appreciated I m learning Xslt , thank you guys.感谢任何帮助我正在学习 Xslt,谢谢你们。
personne1.xml : personne1.xml :
<personnes>
<personne>
<name>aaa</name>
<age>10</age>
<adress>aaaaaa</adress>
</personne>
<personne>
<name>bbb</name>
<age>10</age>
<adress>aaaaaa</adress>
</personne>
<personne>
<name>ccc</name>
<age>20</age>
<adress>cccccc</adress>
</personne>
<personne>
<name>ddd</name>
<age>10</age>
<adress>cccccc</adress>
</personne>
</personnes>
personne2.xml: personne2.xml:
<?xml version="1.0" encoding="UTF-8"?>
<personnes>
<personne>
<id>1111</id>
<quantity>1100</quantity>
</personne>
<personne>
<id>2222</id>
<quantity>2200</quantity>
</personne>
<personne>
<id>3333</id>
<quantity>3300</quantity>
</personne>
<personne>
<id>4444</id>
<quantity>4400</quantity>
</personne>
<personne>
<id>5555</id>
<quantity>5500</quantity>
</personne>
</personnes>
xsltfilePersonnes.xsl: xsltfilePersonnes.xsl:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
version="3.0">
<xsl:variable name="personne2"
select="document('file:test2\personne2.xml')" />
<xsl:accumulator name="pos" as="xs:integer" initial-value="0">
<xsl:accumulator-rule match="personnes" select="0"/>
<xsl:accumulator-rule match="personnes/personne" select="$value + 1"/>
</xsl:accumulator>
<xsl:mode use-accumulators="pos"/>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/*">
<xsl:copy>
<xsl:merge>
<xsl:merge-source select="personne">
<xsl:merge-key select="accumulator-before('pos')"/>
</xsl:merge-source>
<xsl:merge-source for-each-item="$personne2" select="personnes/personne">
<xsl:merge-key select="accumulator-before('pos')"/>
</xsl:merge-source>
<xsl:merge-action>
<xsl:copy>
<xsl:copy-of
select="current-merge-group()[2]/id, name, current-merge-group()[2]/quantity, age, adress"/>
</xsl:copy>
</xsl:merge-action>
</xsl:merge>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
main java :主要Java:
public static void main (String [] args) throws ParserConfigurationException, SAXException, IOException, TransformerException {
Source input = new StreamSource("file:\test2\personne1.xml");
Source xsl = new StreamSource("file:\test2\filexsltFilePersonnes.xsl");
Result output = new StreamResult(new File("file:\test2\resultFile.xml"));
TransformerFactory factory =new net.sf.saxon.TransformerFactoryImpl();
//TransformerFactory.newInstance();
Transformer transformer = factory.newTransformer(xsl);
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.transform(input, output);
}
If you want to use StreamSource(String systemId)
then a valid local absolute file URI would look something like: new StreamSource("file:///C:/test2/xsltFilePersonnes.xsl")
.如果您想使用
StreamSource(String systemId)
那么有效的本地绝对文件 URI 将类似于: new StreamSource("file:///C:/test2/xsltFilePersonnes.xsl")
。
But I think running your Java code in a certain folder (eg C:\\test2
) and then using relative URIs like new StreamSource("xsltFilePersonnes.xsl")
should work as well.但我认为在某个文件夹(例如
C:\\test2
)中运行您的 Java 代码,然后使用像new StreamSource("xsltFilePersonnes.xsl")
这样的相对 URI 应该也能正常工作。
Saxonica also has JAXP samples for 9.8 online here . Saxonica 还在线提供了 9.8 的 JAXP 示例。
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