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Xamarin.forms 使用 php 将图像上传到服务器目录

[英]Xamarin.forms upload image to server directory using php

Now i'm doing project on Xamarin.Forms in Visual Studio 2017. i'm trying to upload image using HttpClient and post file through php code to my server directory.现在我正在 Visual Studio 2017 中的 Xamarin.Forms 上做项目。我正在尝试使用 HttpClient 上传图像并通过 php 代码将文件发布到我的服务器目录。 But the code below here still not working.但是下面的代码仍然无法正常工作。

I can get photo and show on my application but can not upload to server!我可以获取照片并显示在我的应用程序上,但无法上传到服务器!

Please help!请帮忙!

C# file C#文件

async Task GetPhoto(Func<Task<MediaFile>> getPhotoFunc)
        {

            IsEnabled = false;

            try
            {
                var photo = await getPhotoFunc();
                if (photo == null)
                    return;

                Image = null;
                AllPredictions = new List<PredictionModel>();

                Image = SKBitmap.Decode(photo.GetStreamWithImageRotatedForExternalStorage());
                await PredictPhoto(photo);

                IsEnabled = true;

                byte[] bitmapData;
                var stream = new MemoryStream();
                photo.GetStream().CopyTo(stream);
                bitmapData = stream.ToArray();
                var fileContent = new ByteArrayContent(bitmapData);

                fileContent.Headers.ContentType = MediaTypeHeaderValue.Parse("application/octet-stream");
                fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
                {
                    Name = "file",
                    FileName = "image_test.jpg"
                };

                string boundary = "---8393774hhy37373773";
                MultipartFormDataContent multipartContent = new MultipartFormDataContent(boundary);
                multipartContent.Add(fileContent);


                HttpClientHandler clientHandler = new HttpClientHandler();
                HttpClient httpClient = new HttpClient(clientHandler);
                HttpResponseMessage response = await httpClient.PostAsync("http://it2.sut.ac.th/project61_g23/php/upload-image.php", multipartContent);
                response.EnsureSuccessStatusCode();

            }
            catch (Exception ex)
            {
                Crashes.TrackError(ex, new Dictionary<string, string> { { "Action", "Getting predictions" } });
                await Application.Current.MainPage.DisplayAlert("Error", $"An error occured: {ex.Message}", "OK");
            }
            finally
            {
                IsEnabled = true;
            }
        }

PHP code PHP代码

<?php

$uploaddir = '/Uploads/';
$uploadfile = $uploaddir.basename($_FILES['file']['name']);

echo '<pre>';
if (move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile)) {
    echo "File is valid, and was successfully uploaded.\n";
} else {
    echo "Possible file upload attack!\n";
}

echo 'Here is some more debugging info:';
print_r($_FILES);

echo '</pre>';
?>

This is how I do it with Xamarin Forms and PHP.这就是我使用 Xamarin Forms 和 PHP 的方式。 View the code on my website here.这里查看我网站上的代码

C# code is C# 代码是

using Plugin.Media;
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Diagnostics;
using System.IO;
using System.Linq;
using System.Net.Http;
using System.Net.Http.Headers;
using System.Text;
using System.Threading.Tasks;
using Xamarin.Forms;
namespace UploadPicToServer
{
// Learn more about making custom code visible in the Xamarin.Forms previewer
// by visiting https://aka.ms/xamarinforms-previewer
[DesignTimeVisible(false)]
public partial class MainPage : ContentPage
{
public MainPage()
{
InitializeComponent();
}

private async void btnUpload_Clicked(object sender, EventArgs e)
{

if (!CrossMedia.Current.IsPickPhotoSupported)
{
await DisplayAlert("Photos Not Supported", ":( Permission not granted to photos.", "OK");
return;
}
var file = await Plugin.Media.CrossMedia.Current.PickPhotoAsync(new Plugin.Media.Abstractions.PickMediaOptions
{
PhotoSize = Plugin.Media.Abstractions.PhotoSize.Medium,

});

if (file == null)
return;

string fileName = file.Path;
image.Source = ImageSource.FromStream(() =>
{
var stream = file.GetStream();
file.Dispose();
return stream;
});

//UploadImage1(file.AlbumPath);
UploadImage(file.GetStream(), fileName);
}
private async void UploadImage(Stream mfile, string fileName)
{
int authorID = 2;
string username = "yourusername";

var url = "https://yourwebsite.com/ba-add-profile-pic.php";
url += "?id="+ authorID +"&username="+ username; //any parameters you want to send to the php page.

try
{
HttpClient client = new HttpClient();
client.BaseAddress = new Uri("https://yourwebsite.com/");
MultipartFormDataContent form = new MultipartFormDataContent();
//HttpContent content = new StringContent("fileToUpload");
//form.Add(content, "fileToUpload");

var stream = mfile;
StreamContent content = new StreamContent(stream);

//get file's ext
string fileExt = fileName.Substring(fileName.Length - 4);
string fName = "User-Name-Here-123" + fileExt.ToLower();

content.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "fileToUpload",
FileName = fName
};
form.Add(content);
var response = await client.PostAsync(url, form);
var result = response.Content.ReadAsStringAsync().Result;

}
catch (Exception e)
{
//debug
Debug.WriteLine("Exception Caught: " + e.ToString());

return;
}
}

public static byte[] ToArray(Stream s)
{
if (s == null)
throw new ArgumentNullException(nameof(s));
if (!s.CanRead)
throw new ArgumentException("Stream cannot be read");

MemoryStream ms = s as MemoryStream;
if (ms != null)
return ms.ToArray();

long pos = s.CanSeek ? s.Position : 0L;
if (pos != 0L)
s.Seek(0, SeekOrigin.Begin);

byte[] result = new byte[s.Length];
s.Read(result, 0, result.Length);
if (s.CanSeek)
s.Seek(pos, SeekOrigin.Begin);
return result;
}
}
}

And the PHP code is而 PHP 代码是

//parameters send in via querystring
if (!isset($_REQUEST['author']) || !isset($_REQUEST['username']) ) {
die('{"status" : "Bad", "reason" : "Invalid Access"}');
}

$userID = $_REQUEST['author'];
$isGood = false;
try{

$uploaddir = '../someFolderToStoreTheImage/';
$fileName = basename($_FILES['fileToUpload']['name']);
$uploadfile = $uploaddir . basename($_FILES['fileToUpload']['name']);

//CHECK IF ITS AN IMAGE OR NOT
$allowed_types = array ('image/jpeg', 'image/png', 'image/bmp', 'image/gif' );
$fileInfo = finfo_open(FILEINFO_MIME_TYPE);
$detected_type = finfo_file( $fileInfo, $_FILES['fileToUpload']['tmp_name'] );
if ( !in_array($detected_type, $allowed_types) ) {
die ( '{"status" : "Bad", "reason" : "Not a valid image"}' );
}
//

if (move_uploaded_file($_FILES['fileToUpload']['tmp_name'], $uploadfile)) {
//echo "File is valid, and was successfully uploaded.\n";
echo '{"status" : "Success", "reason" "'. $fileName .'"}';
$isGood = true;
} else {
//echo "Possible file upload attack!\n";
echo '{"status" : "Bad", "reason" : "Unable to Upload Profile Image"}';
}

}
catch(Exception $e) {
echo '{"status" : "Bad", "reason" : "'.$e->getMessage().'"}';
}

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