使用Python和正则表达式删除数组初始化代码

Question

I have a .h file that is automatically generated. In this .h file there are arrays that are initialized in the following manner.

char variable_1[1] = { 0 };
char variable_2[16] = 
  {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
char variable_3[128] = 
  {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
   0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
   0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
   0,0,0,0,0,0,0,0,0,0,0};


char variable_4[63] = 
  {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
   0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
char variable_5[1] = { 0 };
char variable_6[32] = 
  {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};

I am using the following regex in Python:

^char\s+variable_\w+\[\w*\]\s*=\s*\{\s*[0,]*\s*\};

This regex will only find variable_1, variable_2, variable_5 and variable_6. However I need find all instances of these arrays and remove the initialization and leave the array names.

char variable_1[1];
char variable_2[16];
char variable_3[128];
char variable_4[63];
char variable_5[1];
char variable_6[32];

Is there a way to accomplish this in Python?

Answer 1

You're not checking for whitespace inside the arrays. Try:

^char\\s+variable_\\w+\\[\\w*\\]\\s*=\\s*\\{\\s*[0,\\s]*\\s*\\};