如何在python中对字符串进行排序？

Question

I cannot find an answer elsewhere on this site, which is why I am asking. My answer is different as it contains alpha-numeric values and will not work with any integer based solution here is a sample of my string:

01768
01785
01799
01804
01818
01821
01835
01849
01852
01866
XXXXX

What can i do to sort these in ascending/descending order, so far i have tried sorted() as it is used for stings, the output of this is ['0', '1', '6', '6', '8'] ['X', 'X', 'X', 'X', 'X'] . i want each separate value to be ordered and not individual characters. Any help is appreciated.

Answer 1

If you want to sort all these strings by their integer value then you can do this :

sorted(arr,key=lambda x:int(x))

Where arr is the list of all those strings.

Answer 2

Using sorted

Ex:

s = """01768
01785
01799
01804
01818
01821
01835
01849
01852
01866"""

print("Ascending")
print( "\n".join(map(str, sorted(map(int, s.splitlines())))) )
print("---")
print("Descending")
print( "\n".join(map(str, sorted(map(int, s.splitlines()), reverse=True))) )

Output:

Ascending
1768
1785
1799
1804
1818
1821
1835
1849
1852
1866
---
Descending
1866
1852
1849
1835
1821
1818
1804
1799
1785
1768

Answer 3

Using this answer as a guide Does Python have a built in function for string natural sort?

alist = ['01768',
'01785',
'01799',
'01804',
'01818',
'01821',
'01835',
'01849',
'01852',
'01866',
'XXXXX']

from natsort import natsorted, ns
r = natsorted(alist, key=lambda y: y.lower())

>>>print(r)
['01768', '01785', '01799', '01804', '01818', '01821', '01835', '01849', '01852', '01866', 'XXXXX']