迭代第一个列表[]中的每个值到另一个列表[]上以形成字典{}

Question

Two list as below

Suits = ["Hearts", "Diamonds", "Clubs", "Spades"]

values = ['A','2','3','4','5','6','7','8','9','10','J','Q','K']

I would like to create a dictionary as below

Cards = {"Hearts" : "A", "Hearts": "2", "Hearts" : "3"......}

Each one of the items in suits should iterate with all the items in the values list. I tried with {}.Fromkeys() but i was not successful.

Please help. Thanks

Answer 1

You are trying to create a dictionary with the same key appearing multiple times, which is not allowed.

Instead you could have something like:

Cards = {"Hearts" : ['A','2',...,'K'], "Diamonds": ['A','2',...,'K'],......}

And the code for this would be:

suits = ["Hearts", "Diamonds", "Clubs", "Spades"] 
values = ['A','2','3','4','5','6','7','8','9','10','J','Q','K']
cards = {}

for suit in suits:
    cards[suit] = values

Answer 2

Going through with your wish would result in a dictionary in which one key has multiple values.

If you want a table with all possible combinations of your lists, where you can filter for either 'Suits' or 'values' you could write it into a pandas.DataFrame:

Suits = ["Hearts", "Diamonds", "Clubs", "Spades"]
values = ['A','2','3','4','5','6','7','8','9','10','J','Q','K']
both = [(onesuit,onevalue) for onesuit in Suits for onevalue in values]

import pandas as pd
pd.DataFrame(both, columns=['Suits', 'values'])