我可以将字符串从二维数组复制到一维数组（Array＆Pointers）

Question

I found quiet tricky in copying string from two dimensional array to one dimensional array. So I made access those value by address. It is working fine inside for loop. Is the one-dimensional array is really copied with two-dimensional array value.

char *str[4] = {"i " "California", "ii " "Texas", "iii " "Florida", "iv " "Washington"};        //two dimensional array
int r = 0, c, i = 0;
char *temp;      //one dimesional array

for(r = 0; r < 4; r++){
    c = 0;
    while(*(str[r]+c) != '\0'){
        printf("%c", *(str[r]+c));
        c++;
        temp = &str[r][c];
        printf("%c", *temp);
    }
    printf("\n");
}

return 0;

Answer 1

You can use calloc for allocation temp pointer memory size.

#include<stdio.h>
#include <stdlib.h>
#include<string.h>

int main()
{
    char *str[4] = {"i " "California", "ii " "Texas", "iii " "Florida", "iv " "Washington"};        //two dimensional array
    int r = 0;

    for(r = 0; r < 4; r++)
    {
        char *temp = (char*) calloc (strlen(str[r]) ,sizeof(char));
        strcpy(temp, str[r]);
        printf("%s", str[r]);
        printf("\n");
        free(temp);
    }
    return 0;
}

Answer 2

assuming:

char array2dim[x][y];

then to create a 1 dimensional array..

char array1dim[x*y];

memcpy( array1dim, array2dim, x*y );