使用模块捆绑器引用html中的构建文件

Question

I'm using the Gulp to build my SCSS, Pug and ES6 assets for my static website. I know it's possible to hash file names and output the files in a different directory.

For my specific example:

• my Pug markdown are found in the ~/src/pages directory and getting built to the ~/public/ directory.
• My SCSS stylesheets are found in the ~/src/stylesheets directory. These are getting built to the and getting ~/public/style directory

My problem is, when I'm referring to my stylesheets files from Pug, I have to refer to the already-built folder like this:

link(rel='stylesheet', href='./style/example.css')

For my IDE, this doesn't make sense, because the style directory doesn't exist in the ~/src/pages directory.

What I would find the most useful is that I can refer to my stylesheets like the example below:

link(rel='stylesheet', href='../stylesheets/example.scss')

Is there any way this is possible or am I completely going in the wrong direction? If not, where am I looking for?

Answer 1

You can use something like gulp-watch for real-time compiling of your .scss files, then your /style/example.css file will exist and it will be recompiled automatically when you modify example.scss

You may need to move some directories around to get everything to link, but you can use watch to build your Pug files too, so your site will always be up to date.

Basically, you make a change on any file in your project and view the update live.

Answer 2

Solution to make the file name like hash

• gulp, for automating our task
• gulp-rev , for renaming our files with random hashes.
• gulp-rev-collector , for switching non-hashed references by hashed-references inside our files.
• rev-del , for deleting non-hashed files in our /dist folder.

Sample code :

gulpfile.js

gulp.task("revision:rename", ["serve"], () =>
  gulp.src(["dist/**/*.html",
            "dist/**/*.css",
            "dist/**/*.js",
            "dist/**/*.{jpg,png,jpeg,gif,svg}"])
  .pipe(rev())
  .pipe(revdel())
  .pipe(gulp.dest("dist"))
  .pipe(rev.manifest({ path: "manifest.json" }))
  .pipe(gulp.dest("dist"))
);

manifest.json

{
  style.css: style-ds9udjvci.css,
  main.js: main-dijds9xc9.min.js
}

For creating our revision update in the file like Rewrite every reference for every key of manifest.json to it's respective value inside every html/json/css/js file (ie: <link href="style.css"> would become <link href="style-ds9udjvci.css">)

gulp.task("revision:updateReferences", ["serve", "revision:rename"], () =>
  gulp.src(["dist/manifest.json","dist/**/*.{html,json,css,js}"])
 .pipe(collect())
 .pipe(gulp.dest("dist"))
);

Answer 3

Gulp cannot automatically change the file paths used inside the htmls. Therefore you will have to use the generated file path for accessing the style files.

Although if you want to have the file path as the folder structure of your scss, then you will have to replace the contents of the pug file after gulp has finished converting it to HTML.

You can convert the html to String and use the .replace method to replace whatever content you want to change and finally parse the string to a HTML document.

Hope this helps!!