[英]How to read binary string array backwards, then convert to decimal int variable? (Without parse)
I do not understand how to code the following into the program: Read string binary array backwards. 我不明白如何将以下代码编码到程序中:向后读取字符串二进制数组。 Check reversed binary array for 1 (I assume if statements).
检查反向二进制数组是否为1(我假设为if语句)。 Assign bit values for each 1 in binary.
为二进制中的每个1分配位值。 Utilize math.pow to get decimal value for each 1. Add all the active bits.
利用math.pow获得每个1的十进制值。将所有活动位相加。
My program needs to do the following: Open a text file (COMPLETED) Text file contains: 我的程序需要执行以下操作:打开一个文本文件(已完成),该文本文件包含:
(33CDAEFFAD)
(032DAE01AD)
(196CDAEFC0)
(21A00D0000)
(100CDAEFFA)
(F3ABCDEFAB)
(29A0EDF301)
(3ABCDEFABC)
Read each hex (COMPLETED) --> 阅读每个十六进制(已完成)->
Convert hex value to binary (COMPLETED) --> 将十六进制值转换为二进制(已完成)->
Convert the binary value to decimal value (LOST) 将二进制值转换为十进制值(LOST)
public static String[] hexToBinary () throws IOException //converts from
hex to binary
{
Scanner inFile = new Scanner(new File("RAMun3"));
String result[] = new String[8]; //created array to hold binary values
String bValue;
String x = "";
String y = "";
int counter = 0;
while (inFile.hasNextLine() && counter <= 7) //reads lines from text
file && stops array from
going out of bounds
{
String line = inFile.nextLine();
Scanner input = new Scanner(line);
String hex = input.next();
for (int i = 0; i < hex.length(); i++) //for loop to convert hex
digits to binary
{
char hexC = hex.charAt(i);
switch (hexC)
{
case ('0'):
bValue = "0000";
break;
case ('1'):
bValue = "0001";
break;
case ('2'):
bValue = "0010";
break;
case ('3'):
bValue = "0011";
break;
case ('4'):
bValue = "0100";
break;
case ('5'):
bValue = "0101";
break;
case ('6'):
bValue = "0110";
break;
case ('7'):
bValue = "0111";
break;
case ('8'):
bValue = "1000";
break;
case ('9'):
bValue = "1001";
break;
case ('A'):
bValue = "1010";
break;
case ('B'):
bValue = "1011";
break;
case ('C'):
bValue = "1100";
break;
case ('D'):
bValue = "1101";
break;
case ('E'):
bValue = "1110";
break;
case ('F'):
bValue = "1111";
break;
default:
bValue = "N/A";
break;
}
x = bValue;
y += x;
}
result[counter] = y;
counter++;
y = "";
}
for (int t = 0; t < result.length; t++)
{
System.out.println(result[t]);
}
return result;
}
public static void reverseResult(String[] y) //Attempt at code for
reversing array
{
for (int i = y.length-1; i>=0; i--)
{
System.out.print(y[i]+" ");
}
}
public static int binToDecimal (){}
public static void main (String args[]) throws IOException //main
{
readFromFile();
hexToBinary();
binToDecimal();
}
}
Expected outputs after conversion: 转换后的预期输出:
222494130093 -- 13651280301 -- 109200469952 -- 144419127296 -- 68935151610 -- 1046559453099 -- 178793607937 -- 252276832956
After reversing every String in result: 反转结果中的每个字符串后:
public static int binToDecimal (){
for(String bin:result){
int dec=0;
for(int i=0;i<bin.length;i++){
dec+=Math.pow(2,i)*(bin.charAt(i)-'0');
}
println("" + dec);
}
}
With "if" statement as you mentioned it: 如您提到的那样,使用“ if”语句:
public static int binToDecimal (){
for(String bin:result){
int dec=0;
for(int i=0;i<bin.length;i++){
if('1' == bin.charAt(i)){
dec+=Math.pow(2,i);
}
}
println("" + dec);
}
}
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