如何评估将在Jupyter Notebook中执行的python脚本的路径

Question

Note: I am not simply asking how to execute a Python script within Jupyter, but how to evaluate a python variable which would then result in the full path of the Python script I was to execute.

In my particular scenario, some previous cell on my notebook generates a path based on some condition.

Example on two possible cases:

1. script_path = /project_A/load.py
2. script_path = /project_B/load.py

Then some time later, I have a cell where I just want to execute the script. Usually, I would just do: %run -i /project_A/load.py

but I want to keep the cell's code generic by doing something like:

%run -i script_path

where script_path is a Python variable whose value is based on the conditions that are evaluated earlier in my Jupyter notebook.

The above would not work because Jupyter would then complain that it cannot find script_path.py .

Any clues how I can have a Python variable passed to the %run magic?

Answer 1

One hacky way would be to change the directory via %cd path

and then run the script with %run -i file.py

E: I know that this is not exactly what you were asking but maybe it helps with your problem.