keyboard.is_pressed() 在 Python 中是如何工作的？

Question

I'm trying to figure out when i press 'u' only 1 times, why is it pressing 'w' infinite times. Print functions don't work neither but if i delet the keyboard.press('w') and keyboard.release('w'), the print functions start to work correctly ( it's printing out 4 until i press a button then it prints out the right number and when i release the button it writes out 4 again)

while True:
    if keyboard.is_pressed('u'):
        keyboard.press('w')
        keyboard.release('w')
        print(0)
    elif keyboard.is_pressed('j'):
        #keyboard.press_and_release('s')
        print(1)
    elif keyboard.is_pressed('k'):
         #keyboard.press_and_release('d')
         print(2)
    elif keyboard.is_pressed('h'):
        #keyboard.press_and_release('a')
        print(3)
    else:
        print(4)
        keyboard.release('w')

Answer 1

I know that it was a year ago, but I have found this question today.

Sooo, according to the Keyboard API :
keyboard.press(hotkey) emulates pressing a hotkey on keyboard.
keyboard.release(hotkey) emulates releasing a hotkey on keyboard.
A hotkey is an key number, key name, or combination of two or more keys.

keyboard.press_and_release(hotkey) or keyboard.send(hotkey) emulates pressing and releasing a key or hotkey.
Pressing and releasing behaviour depends on values of do_press and do_release when using keyboard.send() .

For example:

keyboard.send('space', do_press=True, do_release=True)

will emulate pressing and releasing space key , but:

keyboard.send('space', do_press=False, do_release=True)

will emulate only releasing space key .

keyboard.is_pressed(key) returns True if a specified key has been pressed, and False otherwise


Hope I've helped!