[英]How to get the URL as shown in browser's address bar in JAVA?
I searched for this many times and their is no clear answer for it on the Internet : can I get the URL exactly as it appears in web browser's address bar in Java and, if yes, how ? 我搜索了很多遍,但在Internet上却找不到明确的答案:我能否获得与Java Web浏览器地址栏中显示的URL完全相同的URL,如果可以,该如何获得?
I mean the exact address : for me now, it would be " https://stackoverflow.com/questions/ask ", or "https: //stackoverflow.com/questions/54790941/how-to-get-the-url-as-shown-in-browsers-address-bar-in-java" (without the space between : and /) for this post. 我的意思是确切的地址:对我而言,现在是“ https://stackoverflow.com/questions/ask ”或“ https://stackoverflow.com/questions/54790941/how-to-get-the-url -如在浏览器中显示的地址栏在Java中”(在此和之间不带空格)。
I know that I can't have the "#..." because this is not transmitted by the browser, so this should be an exception. 我知道我不能使用“#...”,因为这不是由浏览器发送的,因此这应该是一个例外。
To make this simple, I would like to have the exact thing has the "window.location.href" in JavaScript. 为简单起见,我希望确切的东西在JavaScript中具有“ window.location.href”。
Thanks ! 谢谢 !
You can do it with HttpServletRequest . 您可以使用HttpServletRequest做到这一点。 I suggest you review the methods of HttpServletRequest.
我建议您回顾一下HttpServletRequest的方法。
For example: 例如:
private String getBaseUrl(HttpServletRequest httpServletRequest) {
final String scheme = httpServletRequest.getScheme() + "://"; // http://
final String serverName = httpServletRequest.getServerName(); // /example.com
final String serverPort = (httpServletRequest.getServerPort() == 80) ? "" : ":" + httpServletRequest.getServerPort(); // 80 or ?
final String contextPath = httpServletRequest.getContextPath(); // /webapp
final String servletPath = httpServletRequest.getServletPath(); // /test/test
return scheme + serverName + serverPort + contextPath + servletPath;
}
Combining the results of getRequestURL() and getQueryString() 合并getRequestURL()和getQueryString()的结果
private String getUrl(HttpServletRequest httpServletRequest) {
final StringBuffer requestUrl = httpServletRequest.getRequestURL();
final String queryString = httpServletRequest.getQueryString();
if (queryString != null) {
requestUrl.append('?');
requestUrl.append(queryString);
}
return requestUrl.toString();
}
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