How to get the URL as shown in browser's address bar in JAVA?

Question

I searched for this many times and their is no clear answer for it on the Internet : can I get the URL exactly as it appears in web browser's address bar in Java and, if yes, how ?

I mean the exact address : for me now, it would be " https://stackoverflow.com/questions/ask ", or "https: //stackoverflow.com/questions/54790941/how-to-get-the-url-as-shown-in-browsers-address-bar-in-java" (without the space between : and /) for this post.

I know that I can't have the "#..." because this is not transmitted by the browser, so this should be an exception.

To make this simple, I would like to have the exact thing has the "window.location.href" in JavaScript.

Thanks !

Answer 1

You can do it with HttpServletRequest . I suggest you review the methods of HttpServletRequest.

For example:

private String getBaseUrl(HttpServletRequest httpServletRequest) {
    final String scheme =   httpServletRequest.getScheme() + "://";  // http://
    final String serverName = httpServletRequest.getServerName();  // /example.com
    final String serverPort = (httpServletRequest.getServerPort() == 80) ? "" : ":" + httpServletRequest.getServerPort(); // 80 or ?
    final String contextPath = httpServletRequest.getContextPath(); // /webapp
    final String servletPath = httpServletRequest.getServletPath(); // /test/test
    return scheme + serverName + serverPort + contextPath + servletPath;
}

Combining the results of getRequestURL() and getQueryString()

private String getUrl(HttpServletRequest httpServletRequest) {
    final StringBuffer requestUrl = httpServletRequest.getRequestURL();
    final String queryString = httpServletRequest.getQueryString();
    if (queryString != null) {
        requestUrl.append('?');
        requestUrl.append(queryString);
    }
    return requestUrl.toString();
}