方法被调用了8次，我不明白为什么？

Question

My test review is asking "How many times will niceHippo () be called?" and the correct answer is 8. I'm having trouble understanding this as no matter how I look at it I'm not seeing how it results in 8. Please help

public class Animals{

    public static String niceHippo()
    {
        String hippo = "Nice Hippo";
        return hippo;
    }

    public static String niceLion(){
        String lion = "Nice Lion";
        return lion;
    }

    public static void main(String[] args){
        int count = 13;
        String stringOut = "I love this class ";
        do
        {
            stringOut = "Animals can be messy ";
            for (int order = 1; order < 5; ++ order)
                for (int copy = 1; copy <= 2; copy++)
                    System.out.println(niceHippo());
            System.out.println(niceLion());
        }while (count != 13);

        count = 13;
        while (count > 10)
        {
            count--;
        }

        System.out.println(stringOut + count);
    }
}

Answer 1

在您的代码中，您要for (int order = 1; order < 5; ++ order)从order = 1到4迭代外循环for (int order = 1; order < 5; ++ order)并且对于每次迭代，将for (int copy = 1; copy <= 2; copy++)复制值for (int copy = 1; copy <= 2; copy++)迭代是1和2以及niceHippo从内环调用，所以作为结果niceHippo正在被呼叫的8倍

Answer 2

For the loop using copy, each time that's ran you print nice hippo twice because copy <=2 Then the loop using order is going to ask that copy loop to run 4 times because order <5

so in the end nice hippo prints 8 times because one loop prints nice hippo twice and its asked to do that 4 times by the outer loop.