Method is being called 8 times and I do not understand why?

Question

My test review is asking "How many times will niceHippo () be called?" and the correct answer is 8. I'm having trouble understanding this as no matter how I look at it I'm not seeing how it results in 8. Please help

public class Animals{

    public static String niceHippo()
    {
        String hippo = "Nice Hippo";
        return hippo;
    }

    public static String niceLion(){
        String lion = "Nice Lion";
        return lion;
    }

    public static void main(String[] args){
        int count = 13;
        String stringOut = "I love this class ";
        do
        {
            stringOut = "Animals can be messy ";
            for (int order = 1; order < 5; ++ order)
                for (int copy = 1; copy <= 2; copy++)
                    System.out.println(niceHippo());
            System.out.println(niceLion());
        }while (count != 13);

        count = 13;
        while (count > 10)
        {
            count--;
        }

        System.out.println(stringOut + count);
    }
}

Answer 1

在您的代码中，您要for (int order = 1; order < 5; ++ order)从order = 1到4迭代外循环for (int order = 1; order < 5; ++ order)并且对于每次迭代，将for (int copy = 1; copy <= 2; copy++)复制值for (int copy = 1; copy <= 2; copy++)迭代是1和2以及niceHippo从内环调用，所以作为结果niceHippo正在被呼叫的8倍

Answer 2

For the loop using copy, each time that's ran you print nice hippo twice because copy <=2 Then the loop using order is going to ask that copy loop to run 4 times because order <5

so in the end nice hippo prints 8 times because one loop prints nice hippo twice and its asked to do that 4 times by the outer loop.