Python：计算一个向量的元素在另外两个向量的元素之间的次数是多少？

Question

Say I have 3 vectors:

v1 = 1,6,7

v2 = 2,5,6

v3 = 3,4,2

I want to count how many times that v1[i] <= v2[i] <= v3[i] (in a Pythonic way of course). For the above example, the answer should be 1 .

Answer 1

尝试这个：

sum(v1[x] <= v2[x] <= v3[x] for x in range(3))

Answer 2

如果v1 ， v2等是numpy.arrays ，则可以执行

np.sum(np.logical_and(v1<v2, v2<v3))