[英]Python: Lucky sevens game (Average number of dice rolls)
I'm trying to write a count function, to calculate the number of rolls it takes to hit 0. And it is returning me the random integer of the diceroll + 1, how do I get it to count the number of times the myroll variable occurs.我正在尝试编写一个计数函数,以计算达到 0 所需的滚动次数。它返回给我骰子 + 1 的随机整数,我如何让它计算 myroll 变量的次数发生。
import random
def luckysevens():
mypot = int(input("Please enter the amount of money you want to in the pot: "))
while mypot > 0:
diceroll = random.randint(1, 6)
print(diceroll)
myroll = (diceroll + diceroll)
if myroll == 7:
mypot = mypot + 4
print("Your roll was a 7 you earned 4$", mypot)
else:
mypot = mypot - 1
print("Your roll was", myroll, "you lost 1$", mypot)
if mypot == 0:
print("Your out of money!")
sum = 0
for count in range(myroll + 1):
sum = sum + count
print(count)
luckysevens()
If you want to count how many rolls before the loop exits, simply add another counter variable.如果您想计算循环退出前的滚动次数,只需添加另一个计数器变量。 I also am assuming you're rolling a couple dice, so added different random calls for each one.
我还假设您正在掷骰子,因此为每个骰子添加了不同的随机调用。
import random
mypot = int(input("Please enter the amount of money you want to in the pot: "))
num_rolls = 0
while mypot > 0:
die_1 = random.randint(1,6)
die_2 = random.randint(1,6)
myroll = die_1 + die_2
num_rolls += 1 # count rolls
if myroll == 7:
mypot = mypot + 4
print("Your roll was a 7 you earned 4$",mypot)
else:
mypot = mypot - 1
print("Your roll was",myroll,"you lost 1$",mypot)
if mypot == 0:
print("Your out of money!")
print 'Num rolls: {}'.format(num_rolls) # print rolls
在输入代码时,它显示语法错误是num_roll
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