[英]Get dependency tree of a particular package in python
I want to get dependencies of a particular package. 我想获取特定程序包的依赖关系。 Using below command I get the complete dependency tree showing all the installed libraries. 使用以下命令,我得到了完整的依赖关系树,其中显示了所有已安装的库。
pipdeptree --json-tree -p numpy pipdeptree --json-tree -p numpy
Is there a way to get only the dependencies of a package in tree form 有没有一种方法可以仅获取树形式的程序包的依赖项
According to the help in pipdeptree -h
, the --json-tree
option overrides the -p
option: 根据pipdeptree -h
的帮助,-- --json-tree
选项将覆盖-p
选项:
--json-tree Display dependency tree as json which is nested the
same way as the plain text output printed by default.
This option overrides all other options (except
--json).
So, unfortunately, it looks like showing the tree of a single package as json is not normally possible. 因此,不幸的是,看起来像显示单个包的树,因为通常无法实现json。 Using just the -p
option without --json-tree
works as expected: 仅使用-p
选项而不使用--json-tree
可以按预期工作:
$ pipdeptree -p numpy
numpy==1.16.2
But unfortunately that is just regular output. 但不幸的是,这只是常规输出。
Of course you could always hack it together by importing pipdeptree into a script: 当然,您总是可以通过将pipdeptree导入脚本中来将其合并在一起:
import pipdeptree
import json
pkgs = pipdeptree.get_installed_distributions()
dist_index = pipdeptree.build_dist_index(pkgs)
tree = pipdeptree.construct_tree(dist_index)
json_tree = json.loads(pipdeptree.render_json_tree(tree, indent=0))
print([package for package in json_tree if package['package_name'] == 'numpy'][0])
outputs 输出
{'required_version': '1.16.2', 'dependencies': [], 'package_name': 'numpy', 'installed_version': '1.16.2', 'key': 'numpy'}
The source code is here if you want to try something like this: https://github.com/naiquevin/pipdeptree/blob/master/pipdeptree.py 如果您想尝试这样的操作,则源代码在这里: https : //github.com/naiquevin/pipdeptree/blob/master/pipdeptree.py
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