从sql中提取字符细节的特定位置

Question

I have database like the image and i want show to t1 details whose name is an 'e' in second position and 'x' in the last position , can any one provide me help how to to achieve this

The table looks like this

T1        T2    T3
vexes      1    2
becw      12    21
extrst    10    10
vin       15    10
new       35    14
det       10    12
het       15    10
cat       53    52
fexx      10    15
fat       12    15
fatsrot   10    15

Answer 1

You can write your query like following.

select * from yourtable
where t1 like '_e%x'

Note :

_ Represents a single character

% Represents zero or more characters

Answer 2

You could achieve it by using SUBSTRING and RIGHT in following:

SELECT *
FROM tbl
WHERE SUBSTRING(t1, 2, 1) = 'e' --2nd character
      AND RIGHT(t1, 1) = 'x' --last character