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Numpy 使用 putmask 和索引替换数组中的值

[英]Numpy replace values in array using putmask and indexing

I would like to replace values in a NumpyArray, in only one column, on several selected rows only, using putmask.我想使用 putmask 替换 NumpyArray 中的值,仅在一列中,仅在几个选定的行上。 I wish to use indexing on the array to be modified as well as the mask used.我希望对要修改的数组以及使用的掩码使用索引。 Therefor I create a nd.array, a mask and and array of desired replacements.因此,我创建了一个 nd.array、一个掩码和所需的替换数组。 as follows:如下:

import numpy as np

a = np.linspace(1,30,30)
a.shape(10,3)
mask = np.random.randint(2, size=8)
replacements = a[[2,4,5,6,7,8],0]*a[[2,4,5,6,7,8],1]

a
array([[ 1.,  2.,  3.],
   [ 4.,  5.,  6.],
   [ 7.,  8.,  9.],
   [10., 11., 12.],
   [13., 14., 15.],
   [16., 17., 18.],
   [19., 20., 21.],
   [22., 23., 24.],
   [25., 26., 27.],
   [28., 29., 30.]])

mask
array([0, 1, 0, 0, 1, 0, 1, 1])

replacements
array([ 56., 182., 272., 380., 506., 650.])

np.putmask(a[[2,4,5,6,7,8],2], mask[2::], replacements)

My expected result would look like this:我的预期结果如下所示:

a
array([[ 1.,  2.,  3.],
   [ 4.,  5.,  6.],
   [ 7.,  8.,  9.],
   [10., 11., 12.],
   [13., 14., 15.],
   [16., 17., 272.],
   [19., 20., 21.],
   [22., 23., 506.],
   [25., 26., 650.],
   [28., 29., 30.]])

But instead I get this:但是我得到了这个:

a
array([[ 1.,  2.,  3.],
   [ 4.,  5.,  6.],
   [ 7.,  8.,  9.],
   [10., 11., 12.],
   [13., 14., 15.],
   [16., 17., 18.],
   [19., 20., 21.],
   [22., 23., 24.],
   [25., 26., 27.],
   [28., 29., 30.]])

Anybody has an idea maybe?有人有想法吗?

Note that you are using fancy indexing, so when using np.putmask you are modifying a copy rather than a sliced view , and thus the original array remains unchanged.请注意,您使用的是花哨的索引,因此在使用np.putmask您正在修改copy而不是 切片视图,因此原始数组保持不变。 You can check this by trying to index using slice notation, np.putmask(a[2:8,2], mask[2::], replacements) for instance, which would in this case modify the values in a .您可以通过使用切片表示法,试图索引检查这个np.putmask(a[2:8,2], mask[2::], replacements)例如,这在这种情况下,修改的值a

What you could do is use np.where and reassign the values to the corresponding indices in a :你可以做的是使用np.where并重新分配值在相应的指标a

a[[2,4,5,6,7,8],2] = np.where(mask[2::], replacements, a[[2,4,5,6,7,8],2])

Output输出

array([[  1.,   2.,   3.],
       [  4.,   5.,   6.],
       [  7.,   8.,  56.],
       [ 10.,  11.,  12.],
       [ 13.,  14., 182.],
       [ 16.,  17., 272.],
       [ 19.,  20., 380.],
       [ 22.,  23., 506.],
       [ 25.,  26., 650.],
       [ 28.,  29.,  30.]])

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