[英]Python 3 - Google protobuf response - decode without .proto file
I have an issue decoding the google protobuf response without .proto file, had implemented with proto file and working fine, but in this case the .proto file is not available. 我有一个问题解码谷歌protobuf响应没有.proto文件,已实现与原型文件和工作正常,但在这种情况下.proto文件不可用。
Using python 3+ and from the tunnel getting this response 使用python 3+并从隧道获得此响应
b'\x08\x00\x12\x88\x01\x08\xda\xc9\x06\x10\xb6\xc9\x03\x18\xa1\x8b\xb8\x01 \x00*\x00:\x00B\x00J\x00R\x00Z\x00b\x00j\x00r\x00z\x00\x80\x01\xe9\x9b\x8c\xb5\x99-\x90\x01d\x98\x01\xea\x9b\x8c\xb5\x99-\xa2\x01\x00\xaa\x01\x00\xb0\x01\x00\xb8\x01\x01\xc0\x0
1\x00\xd1\x01\x00\x00\x00\x00\x00\x00\x00\x00\xd9\x01\x00\x00\x00\x00\x00\x00\x00\x00\xe1\x01\x00\x00\x00\x00\x00\x00\x00\x00\xea\x01\x00\xf0\x01\x01\xf8\x01\x00\x80\x02\x00\x88\x02\x00\x90\x02\x00\x98\x02\x00\xa8\x02\x00\xb0\x02\x00\xb8\x02\x90N\xc0\x02\x00\xc8\x0
2\x00'
There is a way to decode the google ptobuf without .proto file and make it a dict? 有一种方法可以解码谷歌ptobuf没有.proto文件,并使其成为一个字典?
my code to achieve this is below: 我的代码实现如下:
import pika
credentials = pika.PlainCredentials('demo', 'demo')
cp = pika.ConnectionParameters(
host='127.0.0.1',
port=5671,
credentials=credentials,
ssl=False,
)
connection = pika.BlockingConnection(cp)
channel = connection.channel()
def callback(ch, method, properties, body):
print(" [x] Received %r" % body)
channel.basic_consume(callback, queue='demo_queu', no_ack=True)
print(' [*] Waiting for messages. To exit press CTRL+C')
channel.start_consuming()
need to achieve: 需要实现:
to get body and decode it in human readable 获取身体并将其解码为人类可读的
any idea will be appreciated 任何想法将不胜感激
Finally found a workaround by my self, maybe is a primitive way but only this worked for me. 终于找到了我自己的解决方法,也许是一种原始方式,但只有这对我有用。
SOLUTION: 解:
1. Did list with all the descriptors from .proto file 1.列出了.proto文件中的所有描述符
here is .proto file generated for python 3 is too big cant paste content here
https://ufile.io/2p2d6
descriptors = [proto_file.descriptor_1, proto_file.descriptor_2]
2. Loop throw list and pass one by one 2.循环投掷列表并逐个传递
for d in descriptors:
decoded_response = proto_file._reflection.ParseMessage(d, raw_response.body)
3. Check if decoded_response is not blank 3.检查decoding_response是否为空白
if decoded_response:
# descriptor was found
# response is decoded
else:
# no descriptor
4. After decoded response we go parse it into dict: 4.解码后的响应我们将其解析为dict:
from protobuf_to_dict import protobuf_to_dict
decoded_response_to_dict = protobuf_to_dict(decoded_response)
This solution that spent weeks on it finally worked. 这个花费数周时间的解决方案终于奏效了。
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