如何在PHP中使用mysqli_real_escape_string（）转义除换行符以外的所有字符？

Question

I have a text input which can contain special chars that needs to be escaped. But I also want to preserve the newlines. Using PHP's mysql_real_escape_string(), how is it possible to ignore the newline ('\\n') from escaping.

From the official docs of PHP on mysqli_real_escape_string :

mysqli_real_escape_string ( mysqli $link , string $escapestr ) : string

escapestr: The string to be escaped.

Characters encoded are NUL (ASCII 0), \\n, \\r, \\, ', ", and Control-Z.

How is it possible to omit the \\n from this list but keeping the others intact?

Answer 1

Solution 1: You can achieve this by:

• Explode your string to array using \\n .
• Loop the array and have each item escaped.
• Put them back using Implode and \\n as glue.

Code:

<?php
  $array = explode('\n',$stringToEscape);
  $index = 0;
  foreach($array as $string){
   $array[$index] = mysqli_real_escape_string ( $link , $string) ;
   $index++;
  }
  $excapedString = implode('\n',$array);
?>

Solution 2: Another solution:

• Replace \\n with some text (eg # NEWLINE #).
• Do the string escape.
• Replace the text from step 1 to \\n .

Code:

<?php
 $string = '##YOUR STRING TO BE ESCAPED##';
 $stringToEscape = str_replace('\n','#_NEWLINE_#',$string);
 $escapedString = mysqli_real_escape_string ( $link , $stringToEscape ) ;
 $finalString = str_replace('#_NEWLINE_#','\n',$escapedString);
?>

Answer 2

You can use custom escape function like this one:

 function my_escape_function($value) { $search = array("\\\\", "\\x00", "\\r", "'", '"', "\\x1a"); $replace = array("\\\\\\\\","\\\\0", "\\\\r", "\\'", '\\"', "\\\\Z"); return str_replace($search, $replace, $value); }