[英]Convert dataset to xml string with nested repeated xml vice versa
I'm trying to convert the dataset with 2 datatables into xml string with nested repeated xml like below example. 我正在尝试将具有2个数据表的数据集转换为具有嵌套重复xml的xml字符串,如以下示例所示。
Any advice if you have experienced before? 有什么建议吗?
Example: 例:
<Items>
<Code>A001</Code>
<Qty>3</Qty>
<SerialNoList>
<SerialNo>S01</SerialNo>
<SerialNo>S02</SerialNo>
<SerialNo>S03</SerialNo>
</SerialNoList>
</Items>
I have tried with DataRelation for converting dataset to xml but only can get the below format. 我曾尝试使用DataRelation将数据集转换为xml,但只能获得以下格式。
<Items>
<Code>A001</Code>
<Qty>3</Qty>
<SerialNoList>
<SerialNo>S01</SerialNo>
</SerialNoList>
<SerialNoList>
<SerialNo>S02</SerialNo>
</SerialNoList>
<SerialNoList>
<SerialNo>S03</SerialNo>
</SerialNoList>
</Items>
Code: 码:
data.Tables[0].TableName = "Items";
data.Tables[1].TableName = "SerialNoList";
DataRelation dataRelation = data.Relations.Add("SerialNo",
data.Tables[0].Columns["Code"], data.Tables[1].Columns["Code"]);
dataRelation.Nested = true;
data.Tables[1].Columns["Code"].ColumnMapping = MappingType.Hidden;
string xmlString = data.GetXml();
Data : 资料:
1st DataTable (Items)
Code Qty
A001 3
2nd DataTable (SerialNoList)
Code SerialNo
A001 S01
A001 S02
A001 S03
Try following using Xml Linq: 尝试使用Xml Linq进行以下操作:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Globalization;
using System.Xml;
using System.Xml.Linq;
using System.Data;
namespace ConsoleApplication106
{
class Program
{
const string FILENAME = @"c:\temp\test.xml";
static void Main(string[] args)
{
DataSet ds = new DataSet("Code_Serial_No");
DataTable dtCode = new DataTable("Code");
ds.Tables.Add(dtCode);
dtCode.Columns.Add("Code", typeof(string));
dtCode.Columns.Add("Qty", typeof(int));
dtCode.Rows.Add(new object[] { "A001", 3});
DataTable dtSerialNo = new DataTable("Serial_No");
ds.Tables.Add(dtSerialNo);
dtSerialNo.Columns.Add("Code", typeof(string));
dtSerialNo.Columns.Add("SerialNo", typeof(string));
dtSerialNo.Rows.Add(new object[] { "A001", "S01" });
dtSerialNo.Rows.Add(new object[] { "A001", "S02" });
dtSerialNo.Rows.Add(new object[] { "A001", "S03" });
string xml = "<Items></Items>";
XDocument doc = XDocument.Parse(xml);
XElement items = doc.Root;
items.Add(new XElement("Code", ds.Tables["Code"].Rows[0]["Code"]));
items.Add(new XElement("Qty", ds.Tables["Code"].Rows[0]["Qty"]));
XElement list = new XElement("SerialNoList");
items.Add(list);
foreach (DataRow row in ds.Tables["Serial_No"].AsEnumerable())
{
list.Add(new XElement("SerialNo", row.Field<string>("SerialNo")));
}
doc.Save(FILENAME);
}
}
}
For those who need to work with multiple items 对于那些需要处理多个项目的人
//dataSet is filled with data
string xml = "";
foreach (DataRow dr in dataSet.Tables["Items"].Rows)
{
XDocument doc = XDocument.Parse("<Detail></Detail>");
XElement items = doc.Root;
items.Add(new XElement("Code", dr["Code"]));
items.Add(new XElement("Qty", dr["Qty"]));
XElement list = new XElement("SerialNoList");
items.Add(list);
foreach (DataRow row in data.Tables["SerialNoList"].Select("Code = '" + dr["Code"] + "'"))
{
list.Add(new XElement("SerialNo", row["SerialNo"]));
}
xml += doc.ToString();
}
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