编写没有 POW 或乘法的指数函数

Question

Im trying to Write a function that accepts two input parameters and computes the result of raising the value of the first input to the value of the second input, and returns the result. You are not allowed to use the multiplication operator(*)for performing multiplication, nor are you allowed to use any built-in C++ functionality that directly produces the exponentiation result.

Data Types: function works correctly for both inputs being positives, zeroes, or ones, and when the second input is negative. my return is always 0 what am I doing wrong

#include <iostream>

using namespace std;

int exp(int, int);

int main()
{
    int num1, // to store first number
        num2, // to store second number
        value = 0;

    // read numbers
    cout << "Enter first number: ";
    cin >> num1;
    cout << "Enter second number: ";
    cin >> num2;

    // call function
    exp(num1, num2);

    // print value
    cout << "The value of " << num1 << " to the " << num2 << " is: " << value << endl << endl;

    system("pause");
    return 0;
}

// function definition
int exp(int a, int b)
{
    int result = 0;

    for (int i = 0; i < a; i++)
    {
        result += b;
    }
    return result;
}

Answer 1

没错，您正在实现乘法而不是求幂，但是每次都得到 0 的原因是您没有将函数调用的返回值存储在 value 变量中，而是每次都输出零。