我的问题是关于类成员函数的返回类型作为指向类的指针

Question

I have a question about return type of a function as a pointer to class that how it works. Especially treenode* get_left()

class treenode{
private:
   int object;
   treenode* left;
   treenode* right;

public:
   treenode* get_left(){
      return this->left;
   }
};

Answer 1

This function returns a pointer of type Treenode which have 3 attributes: int object, treenode* left and treenode* right.

You can use this pointer as object and call their function.

That is to say, if you have the following tree:

        6 
     4     9

if you do : SixTree.get_left() it returns a pointer to treenode (FourTree in this case) and now you can use: print(FourTree.object) and the result should be :

>> 4