[英]Get results of request with sort and limit using pymongo
Let's take this simple collection col
with 2 documents: 让我们以2个文档作为这个简单的集合
col
:
{
"_id" : ObjectId("5ca4bf475e7a8e4881ef9dd2"),
"timestamp" : 1551736800,
"score" : 10
}
{
"_id" : ObjectId("5ca4bf475e7a8e4881ef9dd3"),
"timestamp" : 1551737400,
"score" : 12
}
To access the last timestamp (the one of the second document), I first did this request 要访问上一个时间戳(第二个文档中的一个),我首先执行了此请求
a = db['col'].find({}).sort("_id", -1)
and then a[0]['timestamp']
然后
a[0]['timestamp']
But as there will be a lot of documents in this collection, i think that it would be more efficient to request only the last one with the limit function, like 但是由于此集合中将有很多文档,我认为只请求带有limit函数的最后一个文档会更有效,例如
a = db['col'].find({}).sort("_id", -1).limit(1)
and then 接着
for doc in a:
lastTimestamp = doc['timestamp']
as there will be only one, i can declare the variable inside the loop. 因为只有一个,所以我可以在循环内声明变量。
So three questions : 所以三个问题:
Thanks ! 谢谢 ! Python 3.6 / Pymongo 3.7
Python 3.6 / Pymongo 3.7
If you are using any field with an unique index in the selection criteria, you should use find_one
method which will return the only document that matches your query. 如果在选择条件中使用具有唯一索引的任何字段,则应使用
find_one
方法,该方法将返回唯一与查询匹配的文档。
That being said, the find
method returns a Cursor object and does not load the data into memory. 就是说,
find
方法返回一个Cursor对象,并且不会将数据加载到内存中。
You might get a better performance if you where using a filter option. 如果使用过滤器选项,则可能会获得更好的性能。 Your query as it is now will do a collection scan.
您现在的查询将进行集合扫描。
if you are not using a filter, and want to retrieve the last document, then the clean way is with the Python built-in next
function. 如果您不使用过滤器,并且想检索最后一个文档,那么干净的方法是使用Python内置的
next
函数。 You could also use the next
method. 您也可以使用
next
方法。
cur = db["col"].find().sort({"_id": -1}).limit(1):
with cur:
doc = next(cur, None) # None when we have empty collection.
find()。sort()是如此之快,不必担心速度,它是访问游标第一个元素的最佳途径。
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