在测试中实例化之前设置静态方法mock

Question

I have an abstract class that calls a static method in it's constructor. However, when writing a test in PHPUnit, when I try to create a mock for it, it complains because the static method is abstract, and thus not defined when constructed.

$interface = $this->getMockForAbstractClass(ConnectionAdapterInterface::class, [[]]);
$interface->method('createConnection')
    ->willReturn(new TestConnection());
$connection = $interface::createConnection();

abstract class ConnectionAdapterInterface
{

    public function __construct(array $configs) {
        $this->connection = static::createConnection($configs);
    }

    abstract public static function createConnection(array $config);

}

It gives the error Static method "createConnection" cannot be invoked on mock object .

Please ignore that the class is called interface; it's one in function but poorly named and I can't think of how else to name it.

Answer 1

静态方法不能被存根或模拟。