[英]C#: Generic method expression with unknown signature
For example we have a generic method 例如,我们有一个通用的方法
public void Test<T>(T param, Action<T> callback)
{
}
If call this method with some parameter, it automatically detect the type of T and we don't need to declare it explicitly. 如果使用某个参数调用此方法,它会自动检测T的类型,我们不需要显式声明它。
For example: 例如:
// here 'int' detected
Test(1, (intVariable) =>
{
});
// here 'string' detected
Test("hello", (stringVariable) =>
{
});
Now, is there any possible way to do the same with methods. 现在,有没有办法用方法做同样的事情。 For example
例如
Test(int.Parse, (parseMethod) =>
{
parseMethod("11");
});
Yes, method/s with the same name can have different signatures and it's impossible to detect which one you want to use as a parameter, but maybe something close possible. 是的,具有相同名称的方法可能具有不同的签名,并且无法检测您要将哪一个用作参数,但可能是可能接近的。
You have to explicitly cast to Func<string, int>
to make this work: 您必须显式转换为
Func<string, int>
才能使其工作:
Test((Func<string, int>)int.Parse, (parseMethod) =>
{
parseMethod("11");
});
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