如何使用python中的计数器库计算唯一单词？

Question

im new to python and trying various libraries

from collections import Counter
print(Counter('like baby baby baby ohhh baby baby like nooo'))

When i print this the output I receive is:

Counter({'b': 10, ' ': 8, 'a': 5, 'y': 5, 'o': 4, 'h': 3, 'l': 2, 'i': 2, 'k': 2, 'e': 2, 'n': 1})

But I want to find the count of unique words:

#output example
({'like': 2, 'baby': 5, 'ohhh': 1, 'nooo': 1}, ('baby', 5))

How can I do this, additionally can I do this without the counter library using loops?

Answer 1

Using the collections.counter you should first split the string into words like so words = 'like baby baby ohhh so forth'.split() Then feed the words variable into the counter.

Yes you can do it without collections module (counter object). There are several ways to do it. One of them, probably not the most efficient one is this:

words = 'like baby baby ohhh so forth'.split()
unique_words = set(words)  # converting to set gets rid of duplicates
wordcount ={}  # an epmty dict
for word in unique_words:
    wordcount[word]=0  # set zero counter for each of the words
for word in words:
    wordcount[word]+= 1  # for each occurrence of a word in the list made fro original string, find that key in dict and increment by 1
print(wordcount)

Answer 2

Try this:

string = 'like baby baby baby ohhh baby baby like nooo'
words = string.split()
result = dict()

for w in words:
    if result.get(w) == None:
        result[w] = 1
    else:
        result[w] += 1

for w in result:
    print(w + ' -- ' + str(result[w]))

Answer 3

The python Counter class takes an Iterable object as parameter. As you are giving it a String object:

Counter('like baby baby baby ohhh baby baby like nooo')

it will iterate over each character of the string and generate a count for each of the different letters. Thats why you are receiving

Counter({'b': 10, ' ': 8, 'a': 5, 'y': 5, 'o': 4, 'h': 3, 'l': 2, 'i': 2, 'k': 2, 'e': 2, 'n': 1})

back from the class. One alternative would be to pass a list to Counter. This way the Counter class will iterate each of the list elements and create the count you expect.

Counter(['like', 'baby', 'baby', 'baby', 'ohhh', 'baby', 'baby', 'like', 'nooo'])

That could also be simply achived by splitting the string into words using the split method:

Counter('like baby baby baby ohhh baby baby like nooo'.split())

Output

Counter({'baby': 5, 'like': 2, 'ohhh': 1, 'nooo': 1})