从以func为参数的func中获取异常

Question

I have one function a that accepts a function func as an argument and returns a new function

how to catch error thrown from a function in function a, because i want to return null from function a when function returns exception. In below case also

Answer 1

Return a new function that calls func wrapped in a try..catch , and remembers whether it has error'd before:

const a = func => {
    let hasThrown = false;

    return function () {
        if (hasThrown) {
            return null;
        }

        try {
            return func(...arguments);
        } catch (e) {
            console.error(e);
            hasThrown = true;
            return null;
        }
    };
};

 const a = func => { let hasThrown = false; return function() { if (hasThrown) { return null; } try { return func(...arguments); } catch (e) { console.error(e); hasThrown = true; return null; } }; }; const getMyName = (name) => { if (name === "jos") { throw new Error(`${name} is wrong`); } return `${name} is yummy`; }; const getName = a(getMyName); console.log(getName("harry")); console.log(getName("garry")); console.log(getName("jos")); console.log(getName("jon")); 

Answer 2

You could surround getCount() inside try and catch

try {
    getCount()
} 
catch(e){
    console.log(e)
}