func() 和 func 一样吗？

Question

While learning JavaScript from an "eloquent" book, I stumbled in this program:

function wrapValue(n) {
  let local = n;
  return () => local;
}

let wrap1 = wrapValue(1);
let wrap2 = wrapValue(2);
console.log(wrap1());
// → 1
console.log(wrap2());
// → 2

My problem is the output being wrap1() rather than wrap1 .

Is it possible to do even console.log(wrap1) ?
And if it's possible, are wrap1() and wrap1 the same thing?

EDIT: they flagged the question as duplicate of What is the difference between a function call and function reference? however my problem was thinking that in let wrap1 = wrapValue(1); , wrap1 gets a value, but the truth is that it gets a function. That's it. The supposed duplicate have nothing to do with my blindness.

Answer 1

wrapValue returns a lambda function, which is what console.log(wrap1) will print. console.log(wrap1()) actually runs that function and prints the result.