[英]Set up default value of the the parameter of the element from the tuple argument
def found( names(String, String) ): Unit {
// Do something
}
The parameter list of the function found is a string tuple (string, string) 找到的函数的参数列表是一个字符串元组(string,string)
How to set up the default value of the second tuple element as the first one like names(String, String=names._1)
Or does this even allowed? 如何将第二个元组元素的默认值设置为第一个元组元素,如
names(String, String=names._1)
还是这样呢? if so how can I passing the argument? 如果是这样,我该如何传递论点?
found( ("FirstName", ???) )
or found("FirstName")
found( ("FirstName", ???) )
或found("FirstName")
If you have a tuple (String, String)
then you have both strings. 如果您有一个元组
(String, String)
那么您将同时拥有两个字符串。 If you have not both strings then this is not a tuple. 如果您没有两个字符串,那么这不是一个元组。 The whole parameter can have default value, part of a tuple can't.
整个参数可以具有默认值,而部分元组则不能。 If default value uses other parameter then parameters should be in different parameter lists.
如果默认值使用其他参数,则参数应位于不同的参数列表中。
Try 尝试
def found(name1: String)(name2: String = name1): Unit = ???
found("FirstName")()
found("FirstName")("LastName")
def foundTuple(names: (String, String)): Unit = found(names._1)(names._2)
foundTuple(("FirstName", "LastName"))
foundTuple("FirstName", "LastName")
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