用python逐个分割列表

Question

I have a list of sentence :

['hello', 'I would like to thank you', 'I would like to thank you. By the way']

I need to split each sentence into list when I found "." .

For example, in the example above, the expected result is :

['hello', 'I would like to thank you', 'I would like to thank you'. 'By the way']

I try with this code in python :

def split_pint(result):
    for i in result:
        i = re.split(r". ", i)
    return result

But the sentence wasn't split.

Any idea please?

Thanks

Answer 1

Using a simple iteration and str.split

Ex:

data = ['hello', 'I would like to thank you', 'I would like to thank you. By the way']

def split_pint(data):
    result = []
    for elem in data:
        result.extend(elem.split(". "))        
    return result

print(split_pint(data))

Output:

['hello', 'I would like to thank you', 'I would like to thank you', 'By the way']

Answer 2

That is not the way to modify a list, as you can see:

l = [0, 0]
for x in l:
    x = 1
print(l)
# [0, 0]

Anyway, if you want to use re.split you'll need to escape . character:

import re

l = ['hello', 'I would like to thank you', 'I would like to thank you. By the way']
def split_pint(result):
    res = []
    for i in result:
        res += re.split("\. ", i)
    return res


print(split_pint(l))
['hello', 'I would like to thank you', 'I would like to thank you', 'By the way']

Answer 3

Another option, but one-liner and in a functional programming way:

>>> from functools import reduce
>>> a = ['hello', 'I would like to thank you', 'I would like to thank you. By the way']
>>> reduce(lambda i, j: i + j, map(lambda s: s.split('. '), a))
['hello', 'I would like to thank you', 'I would like to thank you', 'By the way']

First, map makes a list from each string, and second, reduce just concatenates all lists.