根据Python中列表中包含的句子短语拆分字符串

Question

I want to split a sentence according to the phrases that coincide with the list. Eg:

sentence = "the world is too big"
list = ["too big", "too small", "the world", "too many"]

If the sentence contains a phrase that belongs to the list, the decomposition result it wants to see is:

result = ["the world", "is", "too big"]

Instead of:

result = ["the", "world", "is", "too", "big"]

Thank you so much

Answer 1

sentence = "the world is too big"
list = ["too big", "too small", "the world", "too many"]
for data in list:
  if data in sentence:
   sentence = sentence.replace(data, data.replace(' ', '..............'))
sentence = sentence.split(' ')
for i in range(len(sentence)):
 if '..............' in sentence[i]:
  sentence[i] = sentence[i].replace('..............', ' ')
print(sentence)

Answer 2

Use re.split :

import re

s = "the world is too big"
l = ["too big", "too small", "the world", "too many"]
r = fr"\s*({'|'.join(l)})\s*"

>>> re.split(r, s)[1:-1]
['the world', 'is', 'too big']

>>> r
'\\s*(too big|too small|the world|too many)\\s*'