[英]Why is my original state mutated when filtering with react redux
im using redux in an react app. 即时通讯在React应用程序中使用redux。 Why is this filtering func mutating the original state.products?
为什么此过滤函数会改变原始state.product? I cant understand why
我不明白为什么
state.products = [
{
type: "one",
products: [
{ active: true },
{ active: false }
]
}
]
function mapStateToProps(state) {
const test = state.products.filter((item) => {
if(item.type === "one") {
return item.products = item.products.filter((item) => {
item.active
});
}
return item;
});
return {
machineSearchWeightRange: state.machineSearchWeightRange,
filteredItems: test //This will have only products active
};
}
filteredItems will have only products that is active but the state.products is also updated containing only active products when trying to filter on the same data again. filteredItems将仅具有活动产品,但state.products也将更新,仅在尝试再次过滤相同数据时才包含活动产品。
Suggestions 意见建议
Because you're assigning to a property on an existing state item: 因为您要分配给现有状态项目上的属性,所以:
function mapStateToProps(state) {
const test = state.products.filter((item) => {
if(item.type === "one") {
return item.products = item.products.filter((item) => { // <========== Here
item.active
});
}
return item;
});
return {
machineSearchWeightRange: state.machineSearchWeightRange,
filteredItems: test //This will have only products active
};
}
Instead, create a new item to return. 而是创建一个新项目以返回。 Also, it looks like you need
map
along with filter
, and you're not actually returning item.active
in your inner filter
(see this question's answers for more there): 另外,看起来您需要
map
和filter
,并且实际上item.active
在内部filter
返回 item.active
(有关更多信息,请参阅此问题的答案 ):
function mapStateToProps(state) {
const test = state.products.filter(({type}) => type === "one").map(item => {
return {
...item,
products: item.products.filter((item) => {
return item.active;
})
};
});
return {
machineSearchWeightRange: state.machineSearchWeightRange,
filteredItems: test //This will have only products active
};
}
Side note: This: 旁注:此:
products: item.products.filter((item) => {
return item.active;
})
can be simply: 可以很简单:
products: item.products.filter(({active}) => active)
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