python regex：从字符串创建字典

Question

I have a sting containing multiple informations which I want to save in a dictionary:

s1 = "10:12:01    R1 3    E44"
s2 = "11:11:01    R100    E400"

pattern = "\d{2}:\d{2}:\d{2}(\,\d+)?" + \
          " +" + \
          "[0-9A-Za-z _]{2}([0-9A-Za-z _]{1})?([0-9A-Za-z _]{1})?" + \
          " +" + \
          "[0-9A-Za-z _]{2}([0-9A-Za-z _]{1})?([0-9A-Za-z _]{1})?$"

# --> 

d1 = {"time" : "10:12:01",
      "id1" : "R1 3", 
      "id2" : "E44"}

d2 = {"time" : "11:11:01",
      "id1" : "R100", 
      "id2" : "E400"}

is there a way doing this directly with python re?

Note: I'm aware that there is a similar question here: regex expression string dictionary python , however the formulation is not precisly pointing to what I expact as answer.

Answer 1

If the information is cleanly divided by whitespaces, why not use that information to split the string by whitespace and create the resultant list of dictionaries.
If we have multiple whitespaces, we can ignore those whitespaces while splitting using re.split

import re

#List of strings
li = [ "10:12:01    R1 3    E44", "11:11:01    R100    E400"]

#List of kyes
keys = ['time', 'id1', 'id2']

#Create the dictionary from keys from keys listand values obtained by splitting string on 2 or more whitespaces
result = [{keys[idx]:re.split(r'\s{2,}', s)[idx] for idx in range(len(keys))} for s in li]

print(result)

The output will be

[
{'time': '10:12:01', 'id1': 'R1 3', 'id2': 'E44'}, 
{'time': '11:11:01', 'id1': 'R100', 'id2': 'E400'}
]

Answer 2

>>> import re
>>> pattern = "(?P<time>\d{2}:\d{2}:\d{2}(\,\d+)?) +(?P<id1>[0-9A-Za-z_]{2}([0-9A-Za-z1-9_]{1})?([0-9A-Za-z_]{1})?) +(?P<id2>[0-9A-Za-z_]{2}([0-9A-Za-z1-9_]{1})?([0-9A-Za-z_]{1})?$)"
>>>
>>> s1 = "10:12:01    R123    E44"
>>> print(re.match(pattern, s1).groupdict())
{'time': '10:12:01', 'id1': 'R123', 'id2': 'E44'}