python regex：從字符串創建字典

Question

我有一個字符串，其中包含多種信息，我想保存在字典中：

s1 = "10:12:01    R1 3    E44"
s2 = "11:11:01    R100    E400"

pattern = "\d{2}:\d{2}:\d{2}(\,\d+)?" + \
          " +" + \
          "[0-9A-Za-z _]{2}([0-9A-Za-z _]{1})?([0-9A-Za-z _]{1})?" + \
          " +" + \
          "[0-9A-Za-z _]{2}([0-9A-Za-z _]{1})?([0-9A-Za-z _]{1})?$"

# --> 

d1 = {"time" : "10:12:01",
      "id1" : "R1 3", 
      "id2" : "E44"}

d2 = {"time" : "11:11:01",
      "id1" : "R100", 
      "id2" : "E400"}

有沒有辦法直接用python re做到這一點？

注意：我知道這里有一個類似的問題： regex表達式字符串字典python ，但是表述並沒有精確地指向我作為答案的含義。

Answer 1

如果信息完全由空格分隔，為什么不使用該信息按空格分隔字符串並創建結果字典列表。
如果我們有多個空格，則可以在使用re.split進行拆分時忽略這些空格

import re

#List of strings
li = [ "10:12:01    R1 3    E44", "11:11:01    R100    E400"]

#List of kyes
keys = ['time', 'id1', 'id2']

#Create the dictionary from keys from keys listand values obtained by splitting string on 2 or more whitespaces
result = [{keys[idx]:re.split(r'\s{2,}', s)[idx] for idx in range(len(keys))} for s in li]

print(result)

輸出將是

[
{'time': '10:12:01', 'id1': 'R1 3', 'id2': 'E44'}, 
{'time': '11:11:01', 'id1': 'R100', 'id2': 'E400'}
]

Answer 2

>>> import re
>>> pattern = "(?P<time>\d{2}:\d{2}:\d{2}(\,\d+)?) +(?P<id1>[0-9A-Za-z_]{2}([0-9A-Za-z1-9_]{1})?([0-9A-Za-z_]{1})?) +(?P<id2>[0-9A-Za-z_]{2}([0-9A-Za-z1-9_]{1})?([0-9A-Za-z_]{1})?$)"
>>>
>>> s1 = "10:12:01    R123    E44"
>>> print(re.match(pattern, s1).groupdict())
{'time': '10:12:01', 'id1': 'R123', 'id2': 'E44'}