[英]How to find a character in a string which is not matching the regex pattern
There is a regex and I need to find the character not matching the regex. 有一个正则表达式,我需要找到与正则表达式不匹配的字符。 Then replace the character with "" in. How to achieve this in JAVA?
然后将字符替换为“”。在JAVA中如何实现?
Pattern : ^((?![\|\=\;])[\p{L}\p{N}\p{M}\p{P}\p{Zs}])+$
Sample Text: HAIRCUT $42 PER PERSON
Required output: HAIRCUT 42 PER PERSON
Just negate what you already have. 否定您已经拥有的。
Find (?!(?![|=;])[\\p{L}\\p{N}\\p{M}\\p{P}\\p{Zs}])[\\S\\s]
查找
(?!(?![|=;])[\\p{L}\\p{N}\\p{M}\\p{P}\\p{Zs}])[\\S\\s]
Replace nothing
nothing
https://regex101.com/r/Sn3DuL/1 https://regex101.com/r/Sn3DuL/1
(?!
(?! [|=;] )
[\p{L}\p{N}\p{M}\p{P}\p{Zs}]
)
[\S\s]
You can replace the character matching the regex. 您可以替换与正则表达式匹配的字符。
String myString = "HAIRCUT $42 PER PERSON";
myString = myString.replaceAll("^((?![\|\=\;])[\p{L}\p{N}\p{M}\p{P}\p{Zs}])+$", "");
Result: 结果:
HAIRCUT 42 PER PERSON
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