How to find a character in a string which is not matching the regex pattern

Question

There is a regex and I need to find the character not matching the regex. Then replace the character with "" in. How to achieve this in JAVA?

Pattern : ^((?![\|\=\;])[\p{L}\p{N}\p{M}\p{P}\p{Zs}])+$
Sample Text: HAIRCUT $42 PER PERSON
Required output: HAIRCUT 42 PER PERSON

Answer 1

Just negate what you already have.

Find (?!(?![|=;])[\\p{L}\\p{N}\\p{M}\\p{P}\\p{Zs}])[\\S\\s]
Replace nothing

https://regex101.com/r/Sn3DuL/1

 (?!
      (?! [|=;] )
      [\p{L}\p{N}\p{M}\p{P}\p{Zs}] 
 )
 [\S\s]

Answer 2

You can replace the character matching the regex.

String myString = "HAIRCUT $42 PER PERSON";
myString = myString.replaceAll("^((?![\|\=\;])[\p{L}\p{N}\p{M}\p{P}\p{Zs}])+$", "");

Result:

HAIRCUT 42 PER PERSON