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我如何将字符转换为R中的二进制值

[英]How I convert characters to binary values in R

I have a dataframe with * and - I want to convert * to 1 and - to 0 but I don't know what to do 我有一个带*和 - 的数据框我希望将*转换为1和 - 到0但我不知道该怎么做

This is my dataframe 这是我的数据框架

> head(Patient_036)
       Driver SNV_Organoid_036 INDEL_Organoid_036 Deletion_Organoid_036
ABCB1       *                -                  *                     -
ACVR1B      *                *                  *                     -
ACVR2A      *                *                  -                     -
APC         *                -                  *                     -
ARID1A      *                -                  *                     -
ARID1B      *                *                  -                     -

Any help please? 有什么帮助吗?

Patient_036[Patient_036 == "*"] <- 1
Patient_036[Patient_036 == "-"] <- 0

DATA: 数据:

Patient_036 <- structure(list(Driver = c("1", "1", "1", "1", "1", "1"), SNV_Organoid_036 = c("0", 
"1", "1", "0", "0", "1"), INDEL_Organoid_036 = c("1", "1", "0", 
"1", "1", "0"), Deletion_Organoid_036 = c("0", "0", "0", "0", 
"0", "0")), row.names = c("ABCB1", "ACVR1B", "ACVR2A", "APC", 
"ARID1A", "ARID1B"), class = "data.frame")

In case your dataframe contains factors , you may need df[] <- lapply(df, as.character) at first. 如果您的数据框包含factors ,您可能首先需要df[] <- lapply(df, as.character) This won't be necessary if you add stringsAsFactors = FALSE or something equivalent when you read in the data. 如果在读入数据时添加stringsAsFactors = FALSE或等效的内容,则stringsAsFactors = FALSE

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