我如何將字符轉換為R中的二進制值

Question

我有一個帶*和 - 的數據框我希望將*轉換為1和 - 到0但我不知道該怎么做

這是我的數據框架

> head(Patient_036)
       Driver SNV_Organoid_036 INDEL_Organoid_036 Deletion_Organoid_036
ABCB1       *                -                  *                     -
ACVR1B      *                *                  *                     -
ACVR2A      *                *                  -                     -
APC         *                -                  *                     -
ARID1A      *                -                  *                     -
ARID1B      *                *                  -                     -

有什么幫助嗎？

Answer 1

Patient_036[Patient_036 == "*"] <- 1
Patient_036[Patient_036 == "-"] <- 0

數據：

Patient_036 <- structure(list(Driver = c("1", "1", "1", "1", "1", "1"), SNV_Organoid_036 = c("0", 
"1", "1", "0", "0", "1"), INDEL_Organoid_036 = c("1", "1", "0", 
"1", "1", "0"), Deletion_Organoid_036 = c("0", "0", "0", "0", 
"0", "0")), row.names = c("ABCB1", "ACVR1B", "ACVR2A", "APC", 
"ARID1A", "ARID1B"), class = "data.frame")

如果您的數據框包含factors ，您可能首先需要df[] <- lapply(df, as.character) 。 如果在讀入數據時添加stringsAsFactors = FALSE或等效的內容，則stringsAsFactors = FALSE 。