将元组附加到列表中

Question

I'm new in python. Is it possible to add my tuples to an empty list, but in an ordered way?

The if i not in myTransfer: part is also not ideal I know, but just to get a clearer output. I tried doing it in the code below, but if there's an easier solution would be much appreciated

tupDays = ('Monday', 'Wednesday', 'Monday')
tupAmount = (100,300,100)
myTransfer = []

for a in tupAmount:
    myTransfer.append(a)
    for i in tupDays:
        if i not in myTransfer:
            myTransfer.append(i)

print(myTransfer)

What I wanted to get is :

[100,Monday,200,Wednesday,100,Monday]

Maybe it will be better to put it in a dictionary, so it can become a key-value pairs, like below but I can't seem to grasp the built-in methods I need to use yet.

{
100: 'Monday',
300: 'Tuesday',
100: 'Monday'
}

Thank you so much for the help.

Answer 1

An approach consists in using zip and itertools.chain .
Here I'm assuming that the 2 tuples have the same length.

import itertools

my_transfer = list(itertools.chain(*zip(tupAmount, tupDays)))
# [100, 'Monday', 300, 'Wednesday', 100, 'Monday']

How it works:

1) zip aggregates elements from the two tuples.

>>> list(zip(tupAmount, tupDays))
[(100, 'Monday'), (300, 'Wednesday'), (100, 'Monday')]

2) itertools.chain returns elements from the iterables. The star operator unpacks the list of tuples. This corresponds to:

>>> list(itertools.chain((100, 'Monday'), (300, 'Wednesday'), (100, 'Monday')))
[100, 'Monday', 300, 'Wednesday', 100, 'Monday']

3) finally, list() constructs a list