[英]append tuples to a list
How can I append the content of each of the following tuples (ie, elements within the list) to another list which already has 'something' in it? 如何将以下每个元组的内容(即列表中的元素)附加到已经包含“内容”的另一个列表中? So, I want to append the following to a list (eg: result[]) which isn't empty:
因此,我想将以下内容添加到不为空的列表(例如:result [])中:
l = [('AAAA', 1.11), ('BBB', 2.22), ('CCCC', 3.33)]
Obviously, the following doesn't do the thing: 显然,以下操作无法实现:
for item in l:
result.append(item)
print result
I want to printout: 我要打印输出:
[something, 'AAAA', 1.11]
[something, 'BBB', 2.22]
[something, 'CCCC', 3.33]
result.extend(item)
You can use the inbuilt list()
function to convert a tuple to a list. 您可以使用内置的
list()
函数将元组转换为列表。 So an easier version is: 所以一个简单的版本是:
l = [('AAAA', 1.11), ('BBB', 2.22), ('CCCC', 3.33)]
result = [list(t) for t in l]
print result
Output: 输出:
[['AAAA', 1.1100000000000001],
['BBB', 2.2200000000000002],
['CCCC', 3.3300000000000001]]
You can convert a tuple to a list easily: 您可以轻松地将元组转换为列表:
>>> t = ('AAA', 1.11)
>>> list(t)
['AAAA', 1.11]
And then you can concatenate lists with extend
: 然后可以将列表与
extend
连接起来:
>>> t = ('AAA', 1.11)
>>> result = ['something']
>>> result.extend(list(t))
['something', 'AAA', 1.11])
You will need to unpack the tuple to append its individual elements. 您将需要打开元组的包装以附加其各个元素。 Like this:
像这样:
l = [('AAAA', 1.11), ('BBB', 2.22), ('CCCC', 3.33)]
for each_tuple in l:
result = ['something']
for each_item in each_tuple:
result.append(each_item)
print result
You will get this: 您将获得:
['something', 'AAAA', 1.1100000000000001]
['something', 'BBB', 2.2200000000000002]
['something', 'CCCC', 3.3300000000000001]
You will need to do some processing on the numerical values so that they display correctly, but that would be another question. 您将需要对数值进行一些处理,以使其正确显示,但这将是另一个问题。
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